Solving directly for n is pretty hard. Which is why we can divide this up into two inequalities:
\(2n
and
\(n-4\leq3n+8\)
Let's solve the first one:
\(2n
\(\text{Subtract n from both sides}\)
\(n<-4\)
Now, let's solve the second one:
\(n-4\leq3n+8\)
\(\text{Subtract n from both sides}\)
\(-4\leq2n+8\)
\(\text{Subtract 8 from both sides}\)
\(-12\leq2n\)
\(\text{Divide by 2}\)
\(-6\leq n\)
So, our inequality is now:
\(-6 \leq n < -4\)
Therefore, the integer solutions are:
\(\boxed{-6, -5}\)