#1**+6 **

Solving directly for n is pretty hard. Which is why we can divide this up into two inequalities:

\(2n

and

\(n-4\leq3n+8\)

Let's solve the first one:

\(2n

\(\text{Subtract n from both sides}\)

\(n<-4\)

Now, let's solve the second one:

\(n-4\leq3n+8\)

\(\text{Subtract n from both sides}\)

\(-4\leq2n+8\)

\(\text{Subtract 8 from both sides}\)

\(-12\leq2n\)

\(\text{Divide by 2}\)

\(-6\leq n\)

So, our inequality is now:

\(-6 \leq n < -4\)

Therefore, the integer solutions are:

\(\boxed{-6, -5}\)

ilorty Jul 29, 2020