help with math

The sum is 40500.

Mmm they must end in 1,3,5,7, or 9

1a1        10     sum = 10(101)+450 

3a3         10    sum = 10(303)+450

5a5         10    sum=  10(505)+450

7a7         10

9a9          10

for each a can be any integer from 0 to 9

So I get 50 numbers

The sum of 0+10+20+ ..... 90 = 5(0+90) = 450

10(101)+450

Total sum = 10(101+303+505+707+909) +5*450 = 10*2525 + 1250 = 26500

That is what I get but I haven't checked it for careless errors