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A palindrome is a number that reads the same forward as backward. If a three-digit palindrome is randomly chosen, what is the probability that it is a multiple of 2?

 Jun 27, 2021
 #1
avatar+234 
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To be a multiple of 2, it would have to have a one's digit of 2, 4, 6, 8. (0 is not included as you cannot have a hundredths digit with a 0.) This makes all the possible palindromes xyx, where x is one of these digits, and y is any digit. This gives 4 possibilities for x, and 10 possibilities for y, creating 40 even palindromes. To find all of the 3 digit palindromes, it is again in format xyx, but in this case x can be any number giving 100 possibilities (10*10). 40/100 = 2/5 probability.

 Jun 27, 2021
 #2
avatar+114801 
+1

I think   4/9

the last digit can be 2,4,6,8,    1,3,5,7,9   It cannot be 0 because the first digit cannot be 0

 Jun 29, 2021
edited by Melody  Jun 29, 2021

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