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Prove that  5^{n^3} +1 is divisible by 3^{n+1} for all nonnegative integers 

 

pls help

 

i tried n=0 and found it works and now im using n=k+1 and im stuck
 

 

cphill helpp?

 Jun 25, 2021
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The statement you're trying to prove is obviously false and it's false where you said you checked.  Take n = 0.  Then $5^{n^3}+1 = 5^0+1 = 2$.  Also, $3^{n+1} = 3^1 = 3$.  Obviously 2 is not divisible by 3.
 

 Jun 25, 2021

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