+230 Squares $ABCD$ and $EFGH$ are equal in area. Vertices $B$, $E$, $C$, and $H$ lie on the same line. Diagonal AC is extended to $J$, the midpoint of $GH$. What is the fraction of the two squares that is shaded?
+37146 Welll 1/2 of the upper square is shaded
the triangle on the bottom is 1/2 * 1/2 * 1/2 of the original area of the lower square
= 1/8 of the lower square
2 squarea: [1/2 (square) + 1/8 (square) ] / 2 square = 5/16 area shaded
