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Squares $ABCD$ and $EFGH$ are equal in area. Vertices $B$, $E$, $C$, and $H$ lie on the same line. Diagonal AC is extended to $J$, the midpoint of $GH$. What is the fraction of the two squares that is shaded?

 Mar 5, 2021
 #1
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Welll     1/2 of the upper square is shaded

 

the triangle on the bottom is    1/2 * 1/2 * 1/2  of the original area of the lower square

                                                     = 1/8 of the lower square

    

 

2 squarea:               [1/2 (square) + 1/8 (square) ] / 2 square   = 5/16 area shaded

 Mar 5, 2021

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