+394 A hotel is in the shape of a cylinder, with a circular foundation. The circumference of the foundation is
6 times the radius, increased by 14.84 ft. Find the radius of the circular foundation. Use 3.14 as an approximation for
piπ.
The radius of the foundation is approximately ___ ft
+2446 
This is a diagram for you to reference as I solve for the radius, r.
\(C=6r+14.84\) because of what the given info states. The general formula for the relation of the radius and circumference is \(C=2\pi r\), so \(2\pi r=6r+14.84\). Now, solve for r, in feet.
| \(2\pi r=6r+14.84\) | The problem states to use the approximation of \(\pi=3.14\), so substitute that into the equation. |
| \(2*3.14r=6r+14.84\) | |
| \(6.28r=6r+14.84\) | Subtract 6r from both sides. |
| \(0.28r=14.84\) | Divide by 0.28 from both sides to finally isolate r, the variable I assigned to be the length, in feet, of the radius. |
| \(r=53ft\) | |
