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A hotel is in the shape of a  cylinder, with a circular foundation. The circumference of the foundation is

6 times the radius, increased by 14.84 ft. Find the radius of the circular foundation. Use 3.14 as an approximation for

piπ.

The radius of the foundation is approximately ___ ft

ladiikeiii  Nov 29, 2017
 #1
avatar+556 
0

189 (rounding down)

helperid1839321  Nov 29, 2017
 #2
avatar+2257 
+2

 

This is a diagram for you to reference as I solve for the radius, r.

 

 \(C=6r+14.84\) because of what the given info states. The general formula for the relation of the radius and circumference is \(C=2\pi r\), so \(2\pi r=6r+14.84\). Now, solve for r, in feet.

 

\(2\pi r=6r+14.84\)The problem states to use the approximation of \(\pi=3.14\), so substitute that into the equation.
\(2*3.14r=6r+14.84\) 
\(6.28r=6r+14.84\)Subtract 6r from both sides. 
\(0.28r=14.84\)Divide by 0.28 from both sides to finally isolate r, the variable I assigned to be the length, in feet, of the radius.
\(r=53ft\) 
  
TheXSquaredFactor  Nov 29, 2017

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