A hotel is in the shape of a  cylinder, with a circular foundation. The circumference of the foundation is

6 times the radius, increased by 14.84 ft. Find the radius of the circular foundation. Use 3.14 as an approximation for


The radius of the foundation is approximately ___ ft

 Nov 29, 2017

189 (rounding down)

 Nov 29, 2017


This is a diagram for you to reference as I solve for the radius, r.


 \(C=6r+14.84\) because of what the given info states. The general formula for the relation of the radius and circumference is \(C=2\pi r\), so \(2\pi r=6r+14.84\). Now, solve for r, in feet.


\(2\pi r=6r+14.84\)The problem states to use the approximation of \(\pi=3.14\), so substitute that into the equation.
\(6.28r=6r+14.84\)Subtract 6r from both sides. 
\(0.28r=14.84\)Divide by 0.28 from both sides to finally isolate r, the variable I assigned to be the length, in feet, of the radius.
TheXSquaredFactor  Nov 29, 2017

13 Online Users


New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.