Find the value of B-A if the graph of Bx+Ay=3 passes through the point (-7,2), and is parallel to the graph of x + 3y = -5.
Slope of given line = -B/A = -1/3
Equation of line with this slope passing through (-7,2)
y = (-1/3) (x - - 7) + 2
y = (-1/3)(x + 7) + 2
y = (-1/3)x - 7/3 + 2
y = (-1/3)x - 1/3 multiply through by - 9
-9y = 3x + 3 rewrite as
-3x - 9y = 3
B = -3 A = -9
B - A =
-3 - (-9) = 6
Thank you so much for taking time out of your day to help me with this, but that was not the right answer