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The equation describes the height (in feet) of a projectile launched from the ground at 80 feet per second. At what will the projectile reach 36 feet in height for the first time? Express your answer as a decimal rounded to the nearest tenth.

 Dec 11, 2020
 #1
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The equation is missing......

 Dec 11, 2020
 #2
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 80t - 16t^2  = height

36 = 80t- 16.1 t^2

-16t^2 +80t-36 = 0    Quadratic formula   shows t =  0.5 sec onds for 36 ft height on the way UP

                                                                            t =  4.5 seconds for 36 ft height on the way back down

 Dec 12, 2020

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