The equation describes the height (in feet) of a projectile launched from the ground at 80 feet per second. At what will the projectile reach 36 feet in height for the first time? Express your answer as a decimal rounded to the nearest tenth.
The equation is missing......
80t - 16t^2 = height
36 = 80t- 16.1 t^2
-16t^2 +80t-36 = 0 Quadratic formula shows t = 0.5 sec onds for 36 ft height on the way UP
t = 4.5 seconds for 36 ft height on the way back down