Over the last 3 years salesperson A has earned twice as much as salesperson B, who in turned averaged 50% more then salesperson C. The three combined to make $220 000 over the three years. How much did salesperson B earn on average in any year?
Let salesperson C's earnings =C
Salesperson B's earnings =1.5C
Salesperson A's earnings =3C
C + 1.5C + 3C = $220,000
5.5C = $220,000
C = $220,000 / 5.5
C = $40,000 - total earnings of salesperson C over 3 years.
$40,000 x 1.5 = $60,000 - total earnings of salespeson B over 3 years.
$60,000 / 3 = $20,000 - Salesperson B's average earnings per year for 3 years.
+14915 Over the last 3 years salesperson A has earned twice as much as salesperson B, who in turned averaged 50% more then salesperson C. The three combined to make $220 000 over the three years. How much did salesperson B earn on average in any year?
\(a=2b\\ \color{blue}b=\frac{a}{2}\\ b=1.5c\\ c=\frac{b}{1.5}=\frac{\frac{a}{2}}{1.5}\\ \color{blue}c=\frac{a}{3}\)
\((a+b+c)\cdot 3\ years=220000\$\\ (a+\frac{a}{2}+\frac{a}{3})\cdot 3\ years=220000\$\\ \frac{6a+3a+2a}{2\cdot3}=\frac{220000\$}{3\ years}\\ 11a=\frac{6\cdot 220000\$}{3\ years}\\ a=\frac{6\cdot 220000\$}{11\cdot 3\cdot years}\)
\(a=40000\ \$/year\)
\(b=\frac{a}{2}=\frac{40000}{2}\cdot \frac{\$}{year}\)
\(b=20000\ \$\ /\ year\)
Salesperson B earns 20 000 $ / year.
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