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An actor invested some money at 9 % simple interest, and $41,000

more than three times the amount of 11%. The total annual interest earned from the investment was $47,350.

How much did he invest at each amount?

He invested $ __ at 9 % and $ __ at 11 %.

ladiikeiii Oct 18, 2017

#1**+1 **

An actor invested some money at 9 % simple interest, and $41,000

more than three times the amount of 11%. The total annual interest earned from the investment was $47,350.

How much did he invest at each amount?

Let the amount that he invested @ 11% =A

Then the amount he invested @ 9% =3A + $41,000

11%A + 9%(3A + $41,000) =$47,350

0.11A + 0.27A + $3,690 = $47,350

0.38A +$3,690 = $47,350 Subtract $3,690 from both sides

0.38A = $47,350 - $3,690

0.38A = $43,660 Divide both sides by 0.38

A = $43,660 / 0.38

A = $114,894.74 money invested @ 11%

$114,894.74 x 3 + $41,000 =$385,684.22 money Invsted @ 9%

I was expecting it to come as even dollars, but it didn't unless I fouled something!!.

Guest Oct 19, 2017