2x + y ≥ -4 ⇒ y ≥ -2x - 4
This line will have a negative slope and a y intercept of -4 .it will be solid line because of the " ≥"
y ≥ 2x
This line will also be solid...it will have a positive slope and a y intercept of 0
y - 3 > (1/3) x ⇒ y > (1/3)x + 3
This will be a dashed line with a positive slope and a y intercept of 3
We can eliminate the top left graph and the bottom right graph as these have lines with all positive sopes
Let's pick a point ...say (-1, -1) and see which equations this sattisfies.....notice that this point makes all three equations false...
So...the correct graph must be the one at the top right since the shaded area of this graph graph does not include the point (-1, -1)
y < (-3/4) x + 1
This is a dashed line - because of the "<" - with a negative slope and a y intercept of 1
y > (2/3)x - 3
This is also a dashed line with a positive slope and a y intercept of -3
Note that the graph on the botom right is the only one satisfying these conditions....so, by default...it must be the correct one