Find the slope of the following:

a) A line parallel to the line through the origin and the point (10,11)

b) A line perpendicular to the line that passes through (3,8) and (-1,9)

c) A line parallell to the x-axis

Guest Dec 1, 2017

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Guest
Dec 1, 2017

#1**+1 **

**a)** A line through the origin, which is (0, 0) , and (10, 11) has a slope of

[11 - 0] / [10 - 0] = 11/10

and a line parallel to this also has a slope of 11/10 .

**b)** A line that passes through (3, 8) and (-1, 9) has a slope of

[9 - 8] / [-1 - 3] = 1 / -4 = -1/4

and the slope of a perpendicular line = the negative reciprocal of -1/4 = 4

**c)** A line parallel to the x-axis will not "rise" at all between any two points.

its slope = rise / run = 0 / run = 0

hectictar
Dec 1, 2017

#1**+1 **

Best Answer

**a)** A line through the origin, which is (0, 0) , and (10, 11) has a slope of

[11 - 0] / [10 - 0] = 11/10

and a line parallel to this also has a slope of 11/10 .

**b)** A line that passes through (3, 8) and (-1, 9) has a slope of

[9 - 8] / [-1 - 3] = 1 / -4 = -1/4

and the slope of a perpendicular line = the negative reciprocal of -1/4 = 4

**c)** A line parallel to the x-axis will not "rise" at all between any two points.

its slope = rise / run = 0 / run = 0

hectictar
Dec 1, 2017