If sin x = cos(2x) - 9/8, then find sin x.
Well we get x≈3.3942729+2πn,6.03050505+2πn but i'm not sure of you want a integer or an expression
sin(x) = cos(2x) - 9/8
Using the identity: cos(2x) = 1 - 2sin2(x) ...'
sin(x) = [ 1 - 2sin2(x) ] - 9/8
2sin2(x) + sin(x) + 1/8 = 0
16sin2(x) + 8sin(x) + 1 = 0
[ 4sin(x) + 1 ]2 = 0
4sin(x) + 1 = 0
4sin(x) = -1
sin(x) = -¼