Two cars start from towns 700 mi apart and travel toward each other. They meet after 7 hr. Find the speed of each car if one travels 10 mph faster than the other.
+2862 Distance car 1 traveled = x
Distance car 2 traveled = y
Use formula d=rt
Total distance traveled for both cars = 700
x + y = 700
speed = s
7s = x
7(s + 10) = y
Substitute
7s + 7s + 70 = 700
14s = 630
s = 45
Car 1's speed is 45 mph
Car 2's speed is 55 mph
done
+2862 AoPS doesn't have much good math problems currently, as everyone is crying over their AMC 10 score lol. So I came back here
+1005 Yeah, me too! 52.5 pts for a sixth grader. SOBS!
Don't worry, I'm fine, and PLEASE don't give me any comfort.
Would you like comfort?
+2862 its ok i got a 56 as a 7th grader... we dont talk abou that...
i probably only improved like 20 this time around....
eh who cares its not like it matters anyways im only in middle school
Let the speed of one car =S
The speed of the other =S + 10
7S + 7(S + 10) = 700, solve for S
S =45 mph - speed of one car
45 + 10 =55 mph - speed of the 2nd car.
Two cars start from towns 700 mi apart and travel toward each other. They meet after 7 hr. Find the speed of each car if one travels 10 mph faster than the other.
700 ml / 7hr = 100 mph = 45mph + 55mph
700 / 7 = 100 100 / 2 = 50
1) 50 - 5 = 45 mph
2) 50 + 5 = 55 mph 
