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# help

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What are the solutions to the equation on [0,2π) ?

csc(3x)=−2√3/3

Apr 8, 2020

#1
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What have you done to solve this?

Which quadrants can 3x be in?

If you let    $$\theta=3x$$    Can you draw a right-angled triangle where     $$\csc(\theta)=\frac{2\sqrt3}{3}$$

answer what you can and then get back to me with your responses.