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What are the solutions to the equation on [0,2π) ?

csc(3x)=−2√3/3

 Apr 8, 2020
 #1
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What have you done to solve this?

 

Which quadrants can 3x be in?

 

If you let    \(\theta=3x\)    Can you draw a right-angled triangle where     \(\csc(\theta)=\frac{2\sqrt3}{3}\)

 

 

answer what you can and then get back to me with your responses.

 

 

 

Please no one else come in with a more full answer

     unless guest responds with more than just a 'nothing' answer.

 Apr 8, 2020

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