The perimeter of a rectangular swimming pool is 182 yards. The width of the pool is 7 yards more than five times the length. Find the length and the width.

Guest Feb 3, 2020

#1**+1 **

The perimeter of a rectangle is:

\(2*(L+W)\) where L is the length and W is the width

Given: "The width of the pool is 7 yards more than five times the length"

x+7=5x

Width is x+7

length is 5x

substitute\(2*(5x+(x+7))\) =182 yards

\(10x+2(x+7)=10x+2x+14\)

\(12x+14=182\) yards

subtract 14

\(12x=168\)

Divide by 12 or multiply by (1/12)

\(x=14\)

Thus width is x+7=14+7=21 yards

Length is 5x=5(14)=70

Guest Feb 3, 2020

#3**+1 **

Guest, you should 'check' your answers for 'reasonableness' ...when solving problems...especially on tests !

ElectricPavlov
Feb 3, 2020

#2**+2 **

perimeter = L + L + W + W

and you are given W = 7 + 5L Sub this into the above for W

L + L + W + W = 182

L + L + (7+ 5L) + (7+5L) = 182

12 L + 14 = 182 Now you can solve for L then W = 7 + 5L

ElectricPavlov Feb 3, 2020