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The perimeter of a rectangular swimming pool is 182 yards. The width of the pool is 7 yards more than five times the length. Find the length and the width.

 Feb 3, 2020
 #1
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+1

The perimeter of a rectangle is:

\(2*(L+W)\) where L is the length and W is the width

Given: "The width of the pool is 7 yards more than five times the length" 

x+7=5x 

Width is x+7

length is 5x

substitute\(2*(5x+(x+7))\) =182 yards

\(10x+2(x+7)=10x+2x+14\)

\(12x+14=182\) yards

subtract 14

\(12x=168\)

Divide by 12 or multiply by (1/12)

\(x=14\)

Thus width is x+7=14+7=21 yards

Length is 5x=5(14)=70

 Feb 3, 2020
 #3
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Guest,    you should 'check' your answers for 'reasonableness' ...when solving problems...especially on tests !   cheeky

ElectricPavlov  Feb 3, 2020
 #2
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+2

perimeter =   L + L + W + W

and you are given  W = 7 + 5L    Sub this into the above for W

 

L + L + W + W  =  182

L + L + (7+ 5L) + (7+5L)  = 182

12 L + 14 = 182                              Now you can solve for L      then   W = 7 + 5L

 Feb 3, 2020

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