The perimeter of a rectangular swimming pool is 182 yards. The width of the pool is 7 yards more than five times the length. Find the length and the width.
The perimeter of a rectangle is:
\(2*(L+W)\) where L is the length and W is the width
Given: "The width of the pool is 7 yards more than five times the length"
x+7=5x
Width is x+7
length is 5x
substitute\(2*(5x+(x+7))\) =182 yards
\(10x+2(x+7)=10x+2x+14\)
\(12x+14=182\) yards
subtract 14
\(12x=168\)
Divide by 12 or multiply by (1/12)
\(x=14\)
Thus width is x+7=14+7=21 yards
Length is 5x=5(14)=70
+36916 Guest, you should 'check' your answers for 'reasonableness' ...when solving problems...especially on tests ! 
+36916 perimeter = L + L + W + W
and you are given W = 7 + 5L Sub this into the above for W
L + L + W + W = 182
L + L + (7+ 5L) + (7+5L) = 182
12 L + 14 = 182 Now you can solve for L then W = 7 + 5L
