A group of nine people is be split into three teams, so that one team has four people, one team has three people, and one team has two people. How many ways can this be done?
There are 9 choose 4 = 126 ways to choose the first team.
For the next team, there are 5 remaining people to choose from so there are 5 choose 3 = 10 ways to make it.
The remaining 2 people will be the 2 person team.
126*10= \(\boxed{1260}\) ways to choose the teams.
+218 
