+639 \(\begin{align*} \dbinom{14}{11} &= \dbinom{14}{3} \\ &= \dfrac{14!}{11!3!} \\ &= \dfrac{14\times 13\times 12}{3\times 2\times 1} \\ &= 14 \times 13 \times \dfrac{12}{3\times 2\times 1} \\ &= 14\times 13\times 2 \\ &= \boxed{364}. \end{align*}\)
By the way, I wrote this even though it may look similar to ones on different websites
+639 \(\begin{align*} \dbinom{14}{11} &= \dbinom{14}{3} \\ &= \dfrac{14!}{11!3!} \\ &= \dfrac{14\times 13\times 12}{3\times 2\times 1} \\ &= 14 \times 13 \times \dfrac{12}{3\times 2\times 1} \\ &= 14\times 13\times 2 \\ &= \boxed{364}. \end{align*}\)
By the way, I wrote this even though it may look similar to ones on different websites
+131 You got this from AoPs alcumus right? I mastered it... Anyway:
\(\binom{14}{11}\)= 14 x 13 x 12 x 11...3/ 11!. = 14 x 13 x 12/6 = 26 x 14 = 364
STOP POSTING AOPS QUESTIONS
+188 It was my last one now I will not ask anymore because I understand now for example
11 choose 3 = 11!/3!(11-3
= 165
