+0  
 
0
850
1
avatar

The graph of the equation \(y =ax^2 + bx + c\), where \(a, b, \) and \(c\) are constants, is a parabola with axis of symmetry \(x=-3\) Find \(\frac{b}a\).

 Oct 29, 2018
 #1
avatar+2446 
+2

The axis of symmetry can be found at \(x=\frac{-b}{2a}\), and we know that \(x=-3\), so \(\frac{-b}{2a}=-3\). We can now use algebraic manipulation to solve in terms of \(\frac{b}{a}\).

 

\(\frac{-b}{2a}=-3\\ \frac{b}{2a}=3\\ \frac{b}{a}=6\)

 Oct 29, 2018

2 Online Users