+0

# help!

0
144
1

The graph of the equation $$y =ax^2 + bx + c$$, where $$a, b,$$ and $$c$$ are constants, is a parabola with axis of symmetry $$x=-3$$ Find $$\frac{b}a$$.

Oct 29, 2018

#1
+2340
+1

The axis of symmetry can be found at $$x=\frac{-b}{2a}$$, and we know that $$x=-3$$, so $$\frac{-b}{2a}=-3$$. We can now use algebraic manipulation to solve in terms of $$\frac{b}{a}$$.

$$\frac{-b}{2a}=-3\\ \frac{b}{2a}=3\\ \frac{b}{a}=6$$

.
Oct 29, 2018