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Find the number of integers \(n\) that satisfy \(64 \le n^2 \le 100.\)

 May 20, 2019

Best Answer 

 #2
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Since squaring n makes the product positive, –8, –9, and –10 also satisfy the requirement.

.

 May 20, 2019
 #1
avatar+5662 
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Don't be so lazy.

 May 20, 2019
edited by Rom  May 21, 2019
edited by Rom  May 21, 2019
 #2
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0
Best Answer

 

Since squaring n makes the product positive, –8, –9, and –10 also satisfy the requirement.

.

Guest May 20, 2019
 #3
avatar+703 
+1

in these problems just take the square root of both sides. Remember it can be both positive and negative.

 

It is very simple

 May 20, 2019
 #4
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The answer to the problem is 6. There are 6 numbers, 8, 9, 10, -8, -9, and -10 that satisfy this requirement of this problem.

 

~~Hypotenuisance

 May 21, 2019

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