A cylindrical quarter has a 15/16 inch diameter and a 1/16 inch height. What would be the number of inches in the height of a coin whose volume is exactly four times that of the given quarter and whose diameter equals 1 1/8 inches? Express your answer as a common fraction.
+36916 Volume of the quarter = pi r^2 x h
= pi * (15/16 * 1/2)^2 * 1/16
FOUR times this volume is (the new coin volume)
4 * pi * (15/16 * 1/2)^2 * 1/16
the new coin volume = pi r^2 h also
pi * (9/8 * 1/2)^2 h = 4 * pi * (15/16 * 1/2)^2 * 1/16 solve for the new coin's h
(9/16)^2 h = 1/4 (15/32)^2
h= 25/144
