+633 There are 2 possibilities I see here. I'll solve both.
a) \(2(2-\frac{x}{5})+1\)
First, distribute the parenthesis. That is, multiply the number before the parenthesis by each term inside it 2 and \(\frac{x}{5}\)
We get: \((4-\frac{2x}{5})+1\)
We can now discard the parenthesis and combine like terms: \(5 - \frac{2x}{5}\)
If we want to get a single fraction, we can multiply the 5 by the denominator, placing the value on top as we do so: \(\frac{25-x}{5}\)
b) \(2(\frac{2-x}{5})-1\)
Let's start, again, by distributing the coefficient of the parenthesis: \(\frac{4-2x}{5}-1\)
Now, we put the -1 into the numerator: \(\frac{4-2x-5}{5}\)
Combining like terms, we get: \(\frac{-1-2x}{5}\)
Does that help?
