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# help

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2(2-x/5)+1

Guest May 3, 2017
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There are 2 possibilities I see here. I'll solve both.

a) $$2(2-\frac{x}{5})+1$$

First, distribute the parenthesis. That is, multiply the number before the parenthesis by each term inside it 2 and $$\frac{x}{5}$$

We get: $$(4-\frac{2x}{5})+1$$

We can now discard the parenthesis and combine like terms: $$5 - \frac{2x}{5}$$

If we want to get a single fraction, we can multiply the 5 by the denominator, placing the value on top as we do so: $$\frac{25-x}{5}$$

b) $$2(\frac{2-x}{5})-1$$

Let's start, again, by distributing the coefficient of the parenthesis: $$\frac{4-2x}{5}-1$$

Now, we put the -1 into the numerator: $$\frac{4-2x-5}{5}$$

Combining like terms, we get: ​$$\frac{-1-2x}{5}$$

Does that help?

helperid1839321  May 3, 2017

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