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2(2-x/5)+1

Guest May 3, 2017
 #1
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There are 2 possibilities I see here. I'll solve both.

a) \(2(2-\frac{x}{5})+1\)

First, distribute the parenthesis. That is, multiply the number before the parenthesis by each term inside it 2 and \(\frac{x}{5}\)

We get: \((4-\frac{2x}{5})+1\)

We can now discard the parenthesis and combine like terms: \(5 - \frac{2x}{5}\)

If we want to get a single fraction, we can multiply the 5 by the denominator, placing the value on top as we do so: \(\frac{25-x}{5}\)

b) \(2(\frac{2-x}{5})-1\)

Let's start, again, by distributing the coefficient of the parenthesis: \(\frac{4-2x}{5}-1\)

Now, we put the -1 into the numerator: \(\frac{4-2x-5}{5}\)

Combining like terms, we get: ‚Äč\(\frac{-1-2x}{5}\)

Does that help?

helperid1839321  May 3, 2017

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