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The area of a rectangle is 432 square centimeters. What would the new area be if the length of the rectangle was decreased by %10  and the width of the rectangle was increased by 10% ? Express your answer to the nearest whole number.

 Apr 20, 2019
 #1
avatar+100483 
+1

Old area  = L * W

 

New area  =

 

 ( 1.1L) (.90 W)        

 

 ( 1.1 L) ( .90 W)

 

  L * W *  (1.1) (.9)

 

 L * W  * (.99)

 

So....the new area is just  99%  of 432 cm^2   ≈ 428  cm^2

 

 

cool cool cool

 Apr 20, 2019
 #2
avatar+129 
-3

To solve this problem, let's declare variables.

 

L = length

W = width

 

(.90L)*(1.1W) = .99 of the total area.

 

432*.99 equals 427.68 sq. cm.

 

So 428 sq. cm. is the updated(or changed) area.  

 

~~Hypotenuisance

 Apr 21, 2019

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