The area of a rectangle is 432 square centimeters. What would the new area be if the length of the rectangle was decreased by %10 and the width of the rectangle was increased by 10% ? Express your answer to the nearest whole number.

Guest Apr 20, 2019

#1**+1 **

Old area = L * W

New area =

( 1.1L) (.90 W)

( 1.1 L) ( .90 W)

L * W * (1.1) (.9)

L * W * (.99)

So....the new area is just 99% of 432 cm^2 ≈ 428 cm^2

CPhill Apr 20, 2019

#2**-3 **

To solve this problem, let's declare variables.

L = length

W = width

(.90L)*(1.1W) = .99 of the total area.

432*.99 equals 427.68 sq. cm.

**So 428 sq. cm. is the updated(or changed) area. **

~~Hypotenuisance

Hypotenuisance Apr 21, 2019