I don't understand how to do this problem. It's about permutations.
How many distinct arrangements are possible using the letters in the word CHEER?
Multiple Choice
-60
-50
-40
-20
The number of possible disinct arrangements =
[ Number of letters in the word ] ! / [ Repeats of any letter(s) ] !
So we have
[ 5 ] ! / [ number of repeated E's ] ! =
[ 5 ] ! / [ 2 ] ! =
120 / 2 =
60
a slightly different way of looking at it
\(\text{First choose two slots for the E's }\dbinom{5}{2}\\ \text{Then we have 3 distinct letters that we can make }3! \text{ arrangements with}\\ \dbinom{5}{2}3! = 10\cdot 6 = 60\)
+476 
