+0  
 
-1
318
6
avatar+3654 

Help.

NotSoSmart  Apr 3, 2017

Best Answer 

 #4
avatar+91135 
+2

 

The measure of the angle formed by 2 chords  that intersect inside the circle is 1/2 the sum of the chords' intercepted arcs.

 

So  x   =  (1/2)( measure of arc AB + the measure of arc  CD )  =

 

(1/2) ( 27 + 49)  =

 

(1/2) ( 76)  =

 

38°

 

 

cool cool cool

CPhill  Apr 3, 2017
 #4
avatar+91135 
+2
Best Answer

 

The measure of the angle formed by 2 chords  that intersect inside the circle is 1/2 the sum of the chords' intercepted arcs.

 

So  x   =  (1/2)( measure of arc AB + the measure of arc  CD )  =

 

(1/2) ( 27 + 49)  =

 

(1/2) ( 76)  =

 

38°

 

 

cool cool cool

CPhill  Apr 3, 2017
 #5
avatar+91135 
+2

 

Let me prove this to you, NSS.....

 

Draw  DA

 

Then angle BDA  =  1/2  arc  BA   =  13.5°

 

And angle CAD  = 1/2 arc CD  =  24.5°

 

And angle x   is exterior to triangle DOA

 

And angle ODA = angle BDA 

And angle OAD = angle CAD

 

So by the exterior angle theorem......angle x  =

m

 

 

 

cool cool cool

CPhill  Apr 3, 2017
edited by CPhill  Apr 3, 2017
 #6
avatar+3654 
+1

Thank you so much, you've been really helpful to me a lot thanks! I appreciate it very much.

NotSoSmart  Apr 3, 2017

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