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# Help. ​

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Help.

NotSoSmart  Apr 3, 2017

#4
+91135
+2

The measure of the angle formed by 2 chords  that intersect inside the circle is 1/2 the sum of the chords' intercepted arcs.

So  x   =  (1/2)( measure of arc AB + the measure of arc  CD )  =

(1/2) ( 27 + 49)  =

(1/2) ( 76)  =

38°

CPhill  Apr 3, 2017
#4
+91135
+2

The measure of the angle formed by 2 chords  that intersect inside the circle is 1/2 the sum of the chords' intercepted arcs.

So  x   =  (1/2)( measure of arc AB + the measure of arc  CD )  =

(1/2) ( 27 + 49)  =

(1/2) ( 76)  =

38°

CPhill  Apr 3, 2017
#5
+91135
+2

Let me prove this to you, NSS.....

Draw  DA

Then angle BDA  =  1/2  arc  BA   =  13.5°

And angle CAD  = 1/2 arc CD  =  24.5°

And angle x   is exterior to triangle DOA

And angle ODA = angle BDA

So by the exterior angle theorem......angle x  =

m

CPhill  Apr 3, 2017
edited by CPhill  Apr 3, 2017
#6
+3654
+1

Thank you so much, you've been really helpful to me a lot thanks! I appreciate it very much.

NotSoSmart  Apr 3, 2017