log (x-4)/log (3x-10) = log 1/x
(x-4 ) = (3x-10)/x
x^2 --7x+10 = 0
(x-5)(x-2) = 0 x = 5 or 2 (throw out)
Solve \( \)\( \)\(\log (x - 4) - \log (3x - 10) = \log \frac{1}{x} \)
Hello Guest!
\(\color{BrickRed}\log (x - 4) - \log (3x - 10) = \log \frac{1}{x}\\ \log \large \frac{x-4}{3x-10}=log \frac{1}{x}\\ \large \frac{x-4}{3x-10}= \frac{1}{x}\\ x(x-4)=3x-10\)
\(x^2-4x-3x+10=0\\ x^2-7x+10=0\\ x=\frac{7}{2}\pm\sqrt{(\frac{7}{2})^2-10}\\ x=\frac{7}{2}\pm\sqrt{2.25}\\ x=\frac{7}{2}\pm\frac{3}{2}\)
\(\color{blue}x_1=5\\ x_2=2\ (throw\ out)\)
!