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Let $m$ be a constant not equal to $0$ or $1.$ Then the graph of \[x^2 + my^2 = 4\]is a conic section with two foci. Find all values of $m$ such that the foci both lie on the circle $x^2+y^2=16.$  Enter all possible values of $m,$ separated by commas.

 

what I did: first simplifies the equation to $x^2/4+y^2/(4/m)=1$, then we can see the Foci is $4-4/m$, plugging into the circle equation since they are tangents plugging in I only get one fraction $1/2$, am incorrect since the questions asks for a list

 Mar 5, 2021
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https://web2.0calc.com/questions/please-help-with-this_13

 Mar 5, 2021

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