Hi Davis,
look, study, learn :))
2sqrt(147) + 2sqrt(27) - sqrt(98)
To simplify a square root you must look for a square number that goes into it
square numbers are
\(1^1=1 \qquad \text{not helpful though}\\ 2^2=4\\3^2=9\\4^2=16\\etc\\\)
I can see tht
147 = 49*3
27=9*3
98=49*2
so I have
\(2\sqrt{147} + 2\sqrt{27} - \sqrt{98}\\ =2*\sqrt{49*3} \quad+\quad 2*\sqrt{9*3} \quad-\quad \sqrt{49*2}\\ =2*\sqrt{49}*\sqrt3 \quad+\quad 2*\sqrt9*\sqrt3 \quad-\quad \sqrt{49}*\sqrt2\\ =2*7*\sqrt3 \quad+\quad 2*3*\sqrt3 \quad-\quad7*\sqrt2\\ =14\sqrt3 \quad+\quad 6\sqrt3 \quad-\quad7\sqrt2\\ =20\sqrt3 \quad -\quad7\sqrt2\\\)
After you look and study, ask any questions that you want to :)
Hi Davis,
look, study, learn :))
2sqrt(147) + 2sqrt(27) - sqrt(98)
To simplify a square root you must look for a square number that goes into it
square numbers are
\(1^1=1 \qquad \text{not helpful though}\\ 2^2=4\\3^2=9\\4^2=16\\etc\\\)
I can see tht
147 = 49*3
27=9*3
98=49*2
so I have
\(2\sqrt{147} + 2\sqrt{27} - \sqrt{98}\\ =2*\sqrt{49*3} \quad+\quad 2*\sqrt{9*3} \quad-\quad \sqrt{49*2}\\ =2*\sqrt{49}*\sqrt3 \quad+\quad 2*\sqrt9*\sqrt3 \quad-\quad \sqrt{49}*\sqrt2\\ =2*7*\sqrt3 \quad+\quad 2*3*\sqrt3 \quad-\quad7*\sqrt2\\ =14\sqrt3 \quad+\quad 6\sqrt3 \quad-\quad7\sqrt2\\ =20\sqrt3 \quad -\quad7\sqrt2\\\)
After you look and study, ask any questions that you want to :)