+0  
 
0
60
4
avatar

Please help! I am so confused. Sorry.

Guest Aug 24, 2018
 #1
avatar+91186 
+1

First one

We know the side opposite the missing angle and the hypotenuse....the trig function that relates these two is the sine

 

So  sine (?)  = 22 /41

 

And the sine inverse (arcsin) will give us the angle...so...

 

arcsin (22/41)  = ?  ≈ 32.45°

 

 

cool cool cool

CPhill  Aug 24, 2018
 #2
avatar+91186 
+1

Second one

We have an equilateral triangle  composed of three congruent triangles...

Each  has an included angle of 120°  between two sides of 28

 

The  area is  3*(1/2)(side)^2* sin (120°)  =

 

(3/2)(28)^2 * √3/2  =  

 

(3/4)(784)√3  =

 

588√3  units^2

 

 

cool cool cool

CPhill  Aug 24, 2018
 #3
avatar+91186 
+1

Third one

 

We have decagon  .... it is composed of 10 congruent triangles each with a base of 6yd

The height of each triangle is given by  3 / tan (18°)

 

So...the total area  is  10 (1/2)(base) (height)  =

 

10 (1/2) (6) (3/ tan (18°) =

 

90 / tan (18°)   ≈ 277 yd^2

 

 

cool cool cool

CPhill  Aug 24, 2018
 #4
avatar+91186 
+1

Last one

 

We have a hexagon with a perimeter of 30m....so.....each side  is  30 / 6  =  5m

 

And  we  have  6  congruent triangles  each with an included angle of 60° between two equal sides of 5m

 

So....the total area is

 

6(1/2) (5)^2 sin 60°  =

 

3 * 25 * √3/2  =

 

(3/2)*25√3 m^3  =

 

37.5√3 m^2 ≈  65 m^2

 

 

cool cool cool

CPhill  Aug 24, 2018

18 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.