Mr. Perez is 3 times as old as his daughter now. In 15 years’ time, the sum of their ages will be 86 years. Find their ages now.
Let's use the reverse process. Assume p is Mr.Perez's age and d is his daughter's age. Because there are two people's ages combined, we multiply 15 by 2, =30. 86-30 = 56.The ratio p:d is 3:1, 3+1 = 4, and 56/4 = 14. 14*3 gives us 42.
To check, 42/3 = 14, 42+14+15+15=56+30=86.
Mr.Perez is 42 now, and his daughter is14 now. If you have any questions, don't hesitate to ask. :)
Let the daughter's age now =D
Her dad's age now =3D
D +15 + 3D + 15 =86, solve for D
D = 14 years - daughter's age now
14 x 3 = 42 years - her dad's age now.
Let his daughter's age now = A
And the father's age now = 3A
In 15 years ....his daughter's age = A + 15
And the father's age at that time will be 3A + 15
(A + 15) + (3A + 15) = 86 simplify
4A + 30 = 86 subtract 30 from both sides
4A = 56 divide both sides by 4
A = 14 = his daughter's age now
3A = 3*14 = 42 = her father's age now
I like your thinking for using only one variable- smart! I should do that sometime... You know, from what I know, the probability of me getting the same answer as you is higher than the chances of Melody having the same answer as you... Hmm...