There are four equilateral triangles shown in the figure. The number within each equilateral triangle represents its area.
What is the area of the yellow triangle?
Well since the yellow is equilateral inside another equilateral, we can confirm that logically all three blue triangles are congruent.
The orange triangle and the red triangle are similar.
Using one of the properties of similar triangles, we know that the ratio of the side length of the orange triangle to the side length of the red triangle is 2:3
Because: (2/3)^2 = 4/9 = 20/45
Now we found the ratio and that the blue triangles are congruent, we know that the side length of the orange triangle to the side length of the blue triangle is 2: (2 + 3) = 2:5
That means the AREA must be (according to one of the similarity properties) 4:25
So we calculate the area of the blue triangle and find its 125. ( we also can find it using the red triangle.)
Help! Im stuck too! I got the blue triangle as 125, can someone work off from here?
Looking at this, Im not sure if we can use trigonometry.
We know that one of the blue triangles has a 60 degree angle with two sides in a ratio of 2:3.
Using the Law of Sines ih the lower left blue triangle, we have
sin (a) / s = sin (60) / S (1)
Where a is the angle formed by the side of the yellow triangle and the base of this triangle
And S is the side of the yellow triangle
And s is the side of the orange triangle with an area of 20
And using the Law of Sines in the lower right blue triangle, we have
sin ( 120 - a) / (1.5s) = sin (60) / S (2)
Where (180 - 60 - a) = (120 - a) is the angle formed by the side of the yellow triangle and the base of this triangle
And S is the side of the yellow triangle
And 1.5s is the side of the red triangle
So....equating (1) and (2), we have
sin (a) / s = sin (120 - a) / (1.5 s)
sin (a) = sin (120 - a) / (1.5)
sin (a) = [sin(120) cos(a) - sin (a)cos (120) ] / (3/2)
(3/2)sin (a) = (√3 / 2 )cos (a) + sin (a) (1/2)
3sin (a) = √3 cos (a) + sin a
2sin (a) = √3 cos (a)
sin (a) / cos(a) = √3/2
tan (a) = √3/2
So sin (a) = √ 3 / [ √ [ 3 + 4 ] = √3 / √7
And we can find s as
20 = (√3/4)s^2
80 / √3 = s^2
s = √ [ 80 / √3 ]
And we can find the side of the yellow triangle as
s / sin (a) = S / sin (60)
√ [ 80 / √3 ] / [ √3 / √7 ] = S / [√3/2 ]
S = (√3/2) * √ [ 80 / √3 ] / [ √3 / √7 ] = 2√35 / [4√3 ]
So....the area of the yellow equilateral triangle is
(√3 / 4)S^2 =
(√3/ 4) * (2√35)^2 / √3 =
(1/4) 140 =
140 / 4 =
35 units^2
Gold triangle
Area > A = 20 u²
Side > X = ? X = sqrt [(A/√3)*4] X = 6.796
Red triangle
Area > B = 45 u²
Side > Y = ? Y = sqrt [(B/√3)*4] Y = 10.194
Blue (large) triangle
Area > C = ? C = (Z/2)² * √3 C = 125 u²
Side > Z = ? Z = X + Y Z = 16.99
Blue (small) triangle
Side > a = 6.796
Side > b = 10.194
Side > c = ? c² = sqrt[a² + b² - 2ab*cos(q)] c = 8.99
Angle > q = 60°
Semiperimeter > s = ? s = (a + b + c)/2 s = 12.99
Area > Ab = ? Ab = sqrt[ s(s-a)(s-b)(s-c)] Ab = 30 u²
Yellow triangle
Area > D = ? D = C - 3*Ab D = 35 u²