How many ordered pairs of positive integers satisfy the equation, 1/x + 1/y = 1/6 with x
1/x + 1/y = 1/6
[ x + y ] / xy = 1 / 6
xy / [ x + y ] = 6
xy = 6 [ x + y]
xy = 6x + 6y
xy - 6y = 6x
y ( x - 6) = 6x
y = 6x / (x - 6)
When x = 7 y = 42
When x = 8 , y = 24
When x = 9, y = 18
Whex = 10, y = 15
When x = 12, y = 12
So....these are the solutions...........note..... x and y are abrbitrary......so these answers can be "reversed" for x and y