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 Apr 24, 2020
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Since triangle(ABC) is a right triangle, AC2  =  AB2 + BC2   --->   AC2  =  52 + 32   --->   AC2  =  34  

   --->   AC  =  sqrt(34)

 

To find BD, I'm going to find the area of triangle(ABC) in two ways.

 

First way  --  with base AB and height BC:  Area  =  ½·5·3  =  7.5

Second way  --  with base AC and height D:  7.5  =  ½·sqrt(34)·BD   --->   BD  =  15/sqrt(34)

 

Now, add these parts together ...

 Apr 24, 2020

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