Find the simplest pattern and insert the missing term(s) of each sequence:
1, 11, 21, 1112, 3112, 211213, 312213, 212223, 114213, ?, ...
1 how many of what is that that is (one 1) then you wright it as 11 if its 11 how many of what us that (two 1) then its 21 the next one you wright as "one 2 one 1" then its ( 1211)etc. if it 312211 (one 3 one 1 two 2 two one) then
You must separate the terms of each sequence by commas "," . OK?
The answer is 31121314, each number is counting the quantity of numbers before it in increasing magnitude. (Three ones, one two, one three, one four).