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# help

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Kim spent \$214 on shirts. Fancy shirts cost \$27 and plain shirts cost \$13. If she bought a total of 10, then how many of each kind did she buy?

Feb 17, 2020

#1
+131
+1

Let's say x is the number of fancy shirts Kim bought, and y is the number of plain shirts she bought.

27x + 13y = 214

x + y = 10

This means that x = 10 - y. We can plug 10 - y into the equation 27x + 13y = 214. This gives us 27 ( 10 - y ) + 13y = 214.

Expand: 270 - 27y + 13y = 214. Isolate the variable: 27y - 13 y = 270 - 214. Simplify and divide: y = 4.

To get x, simply minus y (which is 4) from 10.

Now we know that the number of plain shirts Kim bought is 4, and the number of fancy shirts Kim bought is 6.

Please correct me if I'm wrong! <3

Feb 17, 2020

#1
+131
+1

Let's say x is the number of fancy shirts Kim bought, and y is the number of plain shirts she bought.

27x + 13y = 214

x + y = 10

This means that x = 10 - y. We can plug 10 - y into the equation 27x + 13y = 214. This gives us 27 ( 10 - y ) + 13y = 214.

Expand: 270 - 27y + 13y = 214. Isolate the variable: 27y - 13 y = 270 - 214. Simplify and divide: y = 4.

To get x, simply minus y (which is 4) from 10.

Now we know that the number of plain shirts Kim bought is 4, and the number of fancy shirts Kim bought is 6.

Please correct me if I'm wrong! <3

milkcloud Feb 17, 2020
#2
+109450
+2

Good job, milkcloud.....exactly correct  !!!!!

CPhill  Feb 17, 2020
#3
+131
+1

Thanks! : D

milkcloud  Feb 17, 2020
edited by milkcloud  Feb 17, 2020