Two positive real numbers have geometric mean \(\sqrt{3}\) and harmonic mean \(\frac{3}{2}\) Enter the two numbers, separated by commas.
\(\sqrt{x y} = \sqrt{3}\\ \dfrac{2}{\dfrac 1 x + \dfrac 1 y}=\dfrac 3 2\\ \dfrac{2xy}{x+y}=\dfrac 3 2\\ \dfrac{6}{x+y}=\dfrac 3 2\\ x+y = 4\\ xy=3\\ x+\dfrac 3 x = 4\\ x^2-4x+3=0\\ (x-3)(x-1)=0\\ x=3,1\\ (x,y) = (1,3), (3,1)\)
+170 
