help

This was a mistake so I just deleted the answer :/

$P[\text{at least 2 1's}] = 1 - P[\text{0 or 1 1's}]\\ P[\text{0 1's}] = \left(\dfrac 5 6\right)^3 = \dfrac{125}{216}\\ P[\text{1 1}] = \dbinom{3}{1}\left(\dfrac 1 6\right)\left(\dfrac 5 6\right)^2 = \dfrac{25}{72}\\ P[\text{at least 2 1's}] = 1 - \dfrac{125}{216}-\dfrac{25}{72} = \dfrac{2}{27}$