Find the units digit of 1^5 + 2^5 + 3^5 + ... + 123^5.
sumfor(n, 1, 123, n^5) = 591,309,561,876
Find units digit of each term
1^5 is 1
2^5 is 2
3^5 is 3
See the pattern here?
Its 1 + 2 + 3... 121 + 122 + 123
So (123)*(124)/2 = 7626.
The units digit of that number is \(\boxed{\sqrt{6}}\)
looking at the last digit for each one
1+2+3+4+5+6+7+8+9+0 = 45
45*12 = 540
540+1+2+3=546
So I think the last digit is 6
Where did that squareroot come from CalculatorUser?
+2862 
