If $a$ is a constant such that $4x^2 - 12x + a$ is the square of a binomial, then what is $a$?

Guest Jun 26, 2019

#1**+1 **

I don't understand the question, but (2x – 3)^{2} = 4x^{2} – 12x + 9 if your answer is in there somewhere.

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Guest Jun 26, 2019

#3**+6 **

So a square of a binomial would be in the form of \((a + b)^2\). In your case, we have \(4x^2 - 12x + a\), which is supposed to be the square of a binomial.

So your binomial would probably be \((2x - 3)\). Squaring this would give us \(4x^2 - 12x + 9\).

So, \(\boxed{a = 9}\)

.KnockOut Jun 26, 2019