If $a$ is a constant such that $4x^2 - 12x + a$ is the square of a binomial, then what is $a$?
I don't understand the question, but (2x – 3)2 = 4x2 – 12x + 9 if your answer is in there somewhere.
.
4x^2 - 12x + a
We can write
(2x - m)^2 = 4x^2 - 4mx + m^2
This implies that 4m = 12....so m = 3 and m^2 = 9 = "a"
So we have
4x^2 - 12x + 9 = (2x- 3)^2
So a square of a binomial would be in the form of (a+b)2. In your case, we have 4x2−12x+a, which is supposed to be the square of a binomial.
So your binomial would probably be (2x−3). Squaring this would give us 4x2−12x+9.
So, a=9
