+490 The height of an object projected upward from the ground with an initial velocity of 64 feet per second is modeled by the function h(t)=−16t^2+64t , where t is measured in seconds.
How long does it take for the object to return to the ground?
1 s
2 s
3 s
4 s
+36915 When the object hits the ground height (h) will = 0 obviously....substitute this in for h and then solve for t
0 = -16t^2+64t
0 = -16t(t-4) so t = 0 or 4 seconds (0 is the time before it was launched)
+36915 When the object hits the ground height (h) will = 0 obviously....substitute this in for h and then solve for t
0 = -16t^2+64t
0 = -16t(t-4) so t = 0 or 4 seconds (0 is the time before it was launched)
