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The height of an object projected upward from the ground with an initial velocity of 64 feet per second is modeled by the function h(t)=−16t^2+64t , where t is measured in seconds.

How long does it take for the object to return to the ground?

 

1 s

2 s

3 s

4 s

 Feb 20, 2019

Best Answer 

 #1
avatar+17331 
+3

When the object hits the ground   height (h) will = 0   obviously....substitute this in for h and then solve for t

 

0 = -16t^2+64t

0 = -16t(t-4)         so t = 0   or   4 seconds       (0 is the time before it was launched)

 Feb 20, 2019
 #1
avatar+17331 
+3
Best Answer

When the object hits the ground   height (h) will = 0   obviously....substitute this in for h and then solve for t

 

0 = -16t^2+64t

0 = -16t(t-4)         so t = 0   or   4 seconds       (0 is the time before it was launched)

ElectricPavlov Feb 20, 2019

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