The values of a function $f(x)$ are given below: \begin{tabular}{|c||c|c|c|c|c|} \hline $x$ & 3 & 4 & 5 & 6 & 7 \\ \hline $f(x)$ & 10 & 17 & 26 & 37 & 50 \\ \hline \end{tabular}Evaluate $f^{-1}\left(f^{-1}(50)\times f^{-1}(10)+f^{-1}(26)\right)$.
Hard to read but I believe we have the points
(3,10) (4, 17) ( 5, 26) ( 6, 37) and ( 7 , 50) on f (x)
f-1 ( 50) = 7
f-1 (10) = 3
f-1 ( 26) = 5
So..... ( 7 * 3 + 5) = 26
So
f-1 ( 7 * 3 + 5) = f-1 (26) = 5