#1**+1 **

*What is the sum of all possible values of x such that 2x(x-10)=-50?*

Multiply it on out. 2x^{2} – 20x = –50

Add +50 to both sides. This

puts the equation in standard

quadratic equation form. 2x^{2} – 20x + 50 = 0

This will factor. (2x – 10)(x – 5) = 0

Set each factor to zero. 2x – 10 = 0 which means one solution is x = 5

x – 5 = 0 which means the other solution is x = 5

Add the two solutions together and

that sum is the answer to the question. 5 + 5 = **10**

Or would this mean that since both solutions

are 5, then the total would be 5. I think it depends

on how you view the question. Maybe I'm wrong.

.

Guest May 4, 2019

edited by
Guest
May 4, 2019

#1**+1 **

Best Answer

*What is the sum of all possible values of x such that 2x(x-10)=-50?*

Multiply it on out. 2x^{2} – 20x = –50

Add +50 to both sides. This

puts the equation in standard

quadratic equation form. 2x^{2} – 20x + 50 = 0

This will factor. (2x – 10)(x – 5) = 0

Set each factor to zero. 2x – 10 = 0 which means one solution is x = 5

x – 5 = 0 which means the other solution is x = 5

Add the two solutions together and

that sum is the answer to the question. 5 + 5 = **10**

Or would this mean that since both solutions

are 5, then the total would be 5. I think it depends

on how you view the question. Maybe I'm wrong.

.

Guest May 4, 2019

edited by
Guest
May 4, 2019