What is the sum of all possible values of x such that 2x(x-10)=-50?
Multiply it on out. 2x2 – 20x = –50
Add +50 to both sides. This
puts the equation in standard
quadratic equation form. 2x2 – 20x + 50 = 0
This will factor. (2x – 10)(x – 5) = 0
Set each factor to zero. 2x – 10 = 0 which means one solution is x = 5
x – 5 = 0 which means the other solution is x = 5
Add the two solutions together and
that sum is the answer to the question. 5 + 5 = 10
Or would this mean that since both solutions
are 5, then the total would be 5. I think it depends
on how you view the question. Maybe I'm wrong.
.
What is the sum of all possible values of x such that 2x(x-10)=-50?
Multiply it on out. 2x2 – 20x = –50
Add +50 to both sides. This
puts the equation in standard
quadratic equation form. 2x2 – 20x + 50 = 0
This will factor. (2x – 10)(x – 5) = 0
Set each factor to zero. 2x – 10 = 0 which means one solution is x = 5
x – 5 = 0 which means the other solution is x = 5
Add the two solutions together and
that sum is the answer to the question. 5 + 5 = 10
Or would this mean that since both solutions
are 5, then the total would be 5. I think it depends
on how you view the question. Maybe I'm wrong.
.
