A ball travels on a parabolic path in which the height (in feet) is given by the expression \(-16t^2+64t+31\), where \(t\) is the time after launch. What is the maximum height of the ball, in feet?

Logic Jul 30, 2019

#1**+3 **

h = -16t^{2} + 64t + 31

maximum value of h will occur when t = -b / [2a]

that is, when t = -64 / [ 2(-16) ]

Once you know the value of t that produces the maximum value of h ,

plug that value in for t to find the height at that time.

Can you finish it? If you get stuck let us know.

hectictar Jul 30, 2019