A ball travels on a parabolic path in which the height (in feet) is given by the expression \(-16t^2+64t+31\), where \(t\) is the time after launch. What is the maximum height of the ball, in feet?
h = -16t2 + 64t + 31
maximum value of h will occur when t = -b / [2a]
that is, when t = -64 / [ 2(-16) ]
Once you know the value of t that produces the maximum value of h ,
plug that value in for t to find the height at that time.
Can you finish it? If you get stuck let us know.
I'm stuck i got t = 2 but what do I do from now.
Thanks hectictar and CPhill I got 95 is that correct?!?