In the diagram below, ABCD is a parallelogram with AB=42 cm. Arc AD is a semi-circle. The area of the parallelogram is 504cm2, and angle ADC = 60 degrees. Find the area of the shaded region in cm2.
+1490 In the diagram below, ABCD is a parallelogram with AB=42 cm. Arc AD is a semi-circle. The area of the parallelogram is 504cm2, and angle ADC = 60 degrees. Find the area of the shaded region in cm2.
AB = 42cm
Area = 504 cm²
Angle ADC = 60°
504 / 42 = 12
Semi-circle radius r = [12 / sin(60°)] /2 r = 6.928
Shaded region area Ar = ( r² pi ) /2 = 75.398 cm² 
