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Help please!! Graph f(x)=3sin(1/2x)−5. Use 3.14 for π. Use the sine tool to graph the function. The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.

 Jan 26, 2021
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Help please!! Graph f(x)=3sin(1/2x)−5. Use 3.14 for π. Use the sine tool to graph the function. The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.

 

See if this helps.

 

https://www.desmos.com/calculator/ual0qhrsqh

 

Here I have built the function starting with the parent graph of

step 1:  f(x)=sinx

wavelength = 2pi

The graph is on the centre line at  (0,0)

the centre line is y=0 

Amplitude (hight from the centre line) =1

 

With each step click on the little circle to the left of the graph to make the graph visible.

 

step 2:   f(x)=sin(x/2)

the only thing that has changed is the wavelength

It was 2pi now it is TWICE that.    so it is 4pi

Nothing else has changed.

 

Step 3:   f(x)=3sin(x/2)

The 3 will change the amplitude, ao amplituce is now 3.

Nothing else changes

 

Step 4:  (x)=3sin(x/2) - 5

this drops the graph 5 units so that the centre line become y=-5

Nothing else changes.

 

Now I have built the graph that you want from the parent function   f(x)=sinx

 

Please make an effort to understand what I have done. 

You will need to play with the graph a bit.

Getting used to Desmos graphing calc will be an invaluable tool for you anyway.

You can finish the question for yourself now.

 Jan 26, 2021

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