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In the game of Frood, dropping $n$ froods gives a score of the sum of the first $n$ positive integers. For example, dropping five froods scores $1 + 2 + 3 + 4 + 5 = 15$ points. Eating $n$ froods earns $10n$ points. For example, eating five froods earns $10(5) = 50$ points. What is the least number of froods for which dropping them will earn more points than eating them?

 Jun 21, 2020
 #1
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At n = 19 dropping them and eating are DEAD EVEN at 190 points each. Therefore, the least number of froods for which dropping will earn more points than eating then, is when n = 20, at which number [20 x 21] = 210 points for dropping them versus 20 * 10 =200 points for eating them.

 Jun 21, 2020
 #2
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Sorry for the number of typos! [20 * 21] / 2 =210. There are other minor typos. Unfortunately, I cannot "edit" them, but the solution is correct.

Guest Jun 21, 2020
 #3
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its ok, thanks tho

AnimalMaster  Jun 21, 2020

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