In the game of Frood, dropping $n$ froods gives a score of the sum of the first $n$ positive integers. For example, dropping five froods scores $1 + 2 + 3 + 4 + 5 = 15$ points. Eating $n$ froods earns $10n$ points. For example, eating five froods earns $10(5) = 50$ points. What is the least number of froods for which dropping them will earn more points than eating them?

AnimalMaster Jun 21, 2020

#1**0 **

At n = 19 dropping them and eating are DEAD EVEN at 190 points each. Therefore, the least number of froods for which dropping will earn more points than eating then, is when n = 20, at which number [20 x 21] = 210 points for dropping them versus 20 * 10 =200 points for eating them.

Guest Jun 21, 2020