+195 A triangle whose side lengths are whole numbers has one side which measures $25$ inches and a perimeter of $80$ inches. What is the fewest number of inches that can be the length of one of the remaining sides?
+79 I'm sorry guest but thet is wrong
Let $s$ and $\ell$ be the shorter and longer of the remaining sides of the triangle. We are told that $25+s+\ell=80$. By the Triangle Inequality,$$s+25>\ell.$$Adding $\ell$ to both sides of the inequality gives \begin{align*} s+25+\ell &> 2\ell \\ 80 &> 2\ell, \end{align*}so the largest value of $\ell$ is $39$. In that case, $s=80-(25+\ell)=80-64=\boxed{16}$.
