+0  
 
0
313
5
avatar+3636 

Help.

NotSoSmart  Nov 17, 2017
 #1
avatar+502 
+3

x2-1=0 aka third one

Rauhan  Nov 17, 2017
 #2
avatar+90913 
+3

Note, NSS....the two roots are  are x = -1 and x  = 1

 

And when x  = 0.....y is negative

 

Notice that letting x = 0   in the first equation means that y  = -2...this means that the point (0, -2)  should be on the graph....but this point clearly isn't on the graph

 

And letting x = 0   in the second and fourth equations, means that y is positive.....and that's not possible on the graph when  x = 0

 

So....the third equation must be correct.....!!!

 

 

cool cool cool

CPhill  Nov 17, 2017
 #3
avatar+502 
+3

so i was right

Rauhan  Nov 17, 2017
 #4
avatar+90913 
+2

Yep....good job, Rauhan....!!!

 

cool cool cool

CPhill  Nov 17, 2017
 #5
avatar+502 
+2

Well I love maths so I try to solve as many questions i can

Rauhan  Nov 17, 2017

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