+394 In triangle ABC, the angles A and B have the same measure, while the measure of angle C is 42°
larger than the measure of each of A and B. What are the measures of the three angles?
The measure of angle A and the measure of angle B are each ___
+9481 The problem tells us that
A = B
and
C = 42° + A
And we know that the sum of the angles in any triangle is 180° , so
A + B + C = 180° Since A = B , we can substitute A in for B .
A + A + C = 180° Since C = 42° + A , we can substitute 42° + A in for C .
A + A + 42° + A = 180° Combine the 3 A's together.
3A + 42° = 180° Subtract 42° from both sides of the equation.
3A = 138° Divide both sides by 3 .
A = 46°
And B = A so B = 46°
+9481 The problem tells us that
A = B
and
C = 42° + A
And we know that the sum of the angles in any triangle is 180° , so
A + B + C = 180° Since A = B , we can substitute A in for B .
A + A + C = 180° Since C = 42° + A , we can substitute 42° + A in for C .
A + A + 42° + A = 180° Combine the 3 A's together.
3A + 42° = 180° Subtract 42° from both sides of the equation.
3A = 138° Divide both sides by 3 .
A = 46°
And B = A so B = 46°
