The numerator of a certain fraction is 5 less than the denominator. If 3 is subtracted from the numerator and 2 is added to the denominator, the resulting fraction is equal to one half. What is the original fraction?
What your Q describes is
(d-5)/d is the original
now subtract 3 from numerator and add 2 to the denom then = 1/2
(d-5-3)/(d+2) = 1/2 now solve for d then the origianl is (d-5)/d